Inductance of a coil for a given emf and current change

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SUMMARY

The inductance of a coil can be calculated using the formula E = -M(ΔI/Δt). In the discussion, an emf of 2.50V is produced when the current changes from -28.0 mA to 31.0 mA over 12.0 ms. The calculation shows that the inductance M is -0.51 H, confirming that inductance is inherently positive, as per Lenz's Law, which states that the induced emf opposes the change in current. Therefore, the correct interpretation is that the inductance is 0.51 H.

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jena
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Hi,

My Question:

What is the inductance of a coil if the coil produces an emf of 2.50V when the current in it changes form -28.0 mA to 31.0 mA in 12.0 ms?

For this I know I will need to use this equation:

E=-M(delta I)/(delta t)

My problem is that I was wondering if coming up with a negative inductance is alright.

Thank You :smile:
 
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No. The inductance is positive. The induced EMF opposes the increasing current (Lenz's Law) which means that E must be negative (-2.50 V) in your example.
 
So this work is fine then

E=-M(delta I)/(delta t)
2.50 V=(-M((31*10^-3 A) - (-28*10^-3 A)))/(12*10^-3 s)
2.50 V= -M(4.92 A/s)
-M=.51 H
M=-.51 H

Thank You:smile:
 

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