cscott
- 778
- 1
Looking for some help for this equation:
[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]
[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]
The discussion revolves around solving the equation 2 \csc x + 3 \sec x = -\sec x \tan x, which involves trigonometric functions. Participants are exploring methods to manipulate the equation for potential solutions.
The discussion is active, with participants offering suggestions on how to simplify the equation further. There is a recognition of the need to multiply by a specific trigonometric function to aid in simplification, although no consensus on the next steps has been reached.
Participants are clarifying whether the goal is to prove an identity or to find specific values of x that satisfy the equation. This distinction is noted as important for guiding the approach to the problem.
HallsofIvy said:Generally, for a problem like this, the best thing to do is change them all to one function. Do you know how sec x, csc x and tan x are defined?
cscott said:Looking for some help for this equation:
[tex]2 \csc x + 3 \sec x = - \sec x \tan x[/tex]
hotvette said:So, what's the question? Is this an identity that you are trying to prove, or are you trying to solve for x that satisfies the equation?
hotvette said:HallsofIvy had the right idea. You just need to go further. Which trig function could you multiply by to simplify the equation [itex]\frac{2}{\sin x} + \frac{3}{\cos x} = -\frac{1}{\cos x}\cdot\frac{\sin x}{\cos x}[/itex]?