How Does Work Affect Acceleration on an Air Track?

  • Thread starter Thread starter msimard8
  • Start date Start date
  • Tags Tags
    Accleration Work
Click For Summary
SUMMARY

The discussion centers on calculating the acceleration of a 0.100 kg cart pushed on an air track with 0.230 J of work over a distance of 10.0 cm. The user correctly identifies that friction is negligible due to the air track and converts units appropriately. To find acceleration, the user is guided to apply Newton's second law and the definition of work, which relates force, distance, and acceleration. The correct approach involves recognizing that work equals force times distance, leading to the calculation of acceleration.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of the work-energy principle
  • Ability to convert units (e.g., centimeters to meters)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the relationship between work, force, and distance in physics
  • Learn how to apply Newton's second law to calculate acceleration
  • Explore the concept of frictionless motion and its implications
  • Practice solving problems involving work and energy in physics
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding the principles of motion and acceleration in a frictionless environment.

msimard8
Messages
58
Reaction score
0
Here is the queston.

A student in a physics lab pushed a 0.100 kg cart on an air track over a distance of 10.0 cm, doing 0.230 J of work. Calculate the acceleration of the cart.

The textbook doesn't show how to approach this problem. It is suppose to be bonus or somthing.

These are my thoughts

I am assuming there is no friction since the cart was on a air track

I converted everything to their proper units.

mass=0.100kg
w=0.0230 J
d =10.0 cm = 0.1m

I know acceleration is change of velocity/time

I need a hint at least to figure out how to solve this.

Thanks
 
Physics news on Phys.org
First, think of acceleration in terms of Newton's second law...

You have been given the amount of work done on the cart and the distance that work was performed. What is the definition of work? What is left to calculate from that definition, i.e. you have been given two things and there are three things in the basic definition for work.

Also, you have one too many leading zeros in the work number when you showed converting to proper units.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 17 ·
Replies
17
Views
6K
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
10K
  • · Replies 10 ·
Replies
10
Views
14K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
1
Views
11K