The discussion revolves around calculating the work required to position a 150kg satellite into a geostationary orbit. Participants are exploring concepts related to gravitational potential energy and kinetic energy in the context of orbital mechanics.
The discussion is ongoing, with some participants offering hints about energy considerations for lifting and accelerating the satellite. There is a lack of explicit consensus on the correct approach, and multiple interpretations of the problem are being explored.
One participant notes the absence of a textbook, which may limit access to necessary formulas and concepts for solving the problem. There is also mention of potential misunderstandings regarding the application of gravitational force equations.
Unfortunately, you don't know that! That's saying "kinetic energy equals potential energy" which applies when you have an object losing kinetic energy (perhaps by rolling down hill) and converting it to kinetic energy (conservation of energy). That is not what happens here. You use the rocket fuel to give the satellite enough potential energy to reach the correct height and enough kinetic energy to reach the correct speed for an orbit at that height.UnD said:1/2 mv^2 = mgh
i know that only
Unfortunately, you don't know that either. In fact, it makes no sense as the two sides have different units. You are probably half-remembering that gravitational force between two objects of masses M and m, distance r apart, is -GmM/r^2. If this is homework, don't you have your textbook in front of you?Umm I know the -Gm=m/r^2
but i don't think it applies to this kind of question.
Plz help