How do the dots in inductor circuits indicate polarity and current direction?

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SUMMARY

The discussion centers on the polarity and current direction in inductor circuits, specifically regarding the placement of dots on inductors A-B and C-D. The user describes a circuit with two inductors where the current (i1) is a triangular wave and the voltage (v2) is a step wave. It is concluded that the dots indicating polarity should be placed on opposite sides of the inductors, confirming the relationship between voltage and the derivative of current, which includes a negative sign.

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EvLer
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one more electro-magnetic question:
here's the set-up: two inductors, the A-B has a signal source hooked-up, C-D is open circuit.
Code:
->i1
A       C 
)    (    +
)    (    V2
)    (    -
B       D

i1 is given as a triangular wave, v2 as a step wave for:
0 < t < 0.5, i1 has negative slope below t-axis, v2=4;
0.5<t<1, i1 has positive slope below t-axis, v2 = -4;
1<t<1.5, i1 has positive slope above t-axis, v2 = 0

so, i clearly see that voltage is derivative of current and there is a negative sign involved, so the dots are placed diagonally?
If not, could you explain that as well?
Thanks in advance...
 
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solved

well... yeah, they should be on the opposite side, i think i got the idea...
 

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