## Short Question

Hi people.
I have a short question from a homework. given a family with 3 children, the sexes of which are unknown: if the eldest child is a boy and there is at least one other boy, then what is the probability one child is a girl?
To me it seems obvious that there are at least two boys from this info, then either there are 3 boys or 2 boys and 1 girl, so the probability one child is a girl is 0.5. Is this method correct?
Thanks,
JB
 Recognitions: Gold Member Science Advisor Staff Emeritus A family with three children and the eldest is a boy. Writing B for boy, G for girl, from oldest to youngest, the possibilities are: BBB BBG BGB BGG Assuming "boy" or "girl" are equally likely at each birth, these are equally likely. But we are told that at least one child is a boy: that throws out BGG leaving BBB BBG BGB and they are still equally likely. Since 2 of those 3 correspond to "one child is a girl", the probability that one of the children is a girl is 2/3, not 1/2. Yes, it is true that there must be "either 3 boys or 2 boys and a girl", but those are NOT "equally likely".
 As far as I'm concerned you should better explain the underlying reason: probability of each sex child birth is fifty-fifty. In a formal proof is often request.