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tricky complex numbers proof |
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| Nov8-05, 08:08 PM | #1 |
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tricky complex numbers proof
I recently was confronted by this monstrosity of a question in one of my mock exams.
|Z1 + Z2| ≤ |Z1| + |Z2| I made a few attempts at it before becoming demoralized with the lack of progress.. |Z^2| was equal to Z1(conjugate)Z1 Hence equaling X^2 + Y^2 However even when expanding into x+iy form etc no avail, help is appreciated. |
| Nov8-05, 08:51 PM | #2 |
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square both side and see if you notice anything and remember
if A=A then, surely A is less than or equal to A |
| Nov9-05, 07:36 AM | #3 |
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Recognitions:
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Geometrically this is just the triangle inequality. It just says that the sum of two sides of a triangle is always greater or equal than the third.
Since you know |z|^2=z*z. Why not write the left side out in this form? ie: |z+w|^2=(z*+w*)(z+w) |
| Nov17-05, 05:01 AM | #4 |
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tricky complex numbers proof
I'm sorry but I had to laugh when I read "I recently was confronted by this monstrosity of a question..." only to find the triangle inequality beneathe. lol.
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