Calculating New Period of a Collapsed Sun Using Conservation of Angular Momentum

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SUMMARY

The discussion centers on calculating the new period of a collapsed sun using the principle of conservation of angular momentum. Given a sun with an initial radius of 8.1 x 10^8 m and a period of 38 days, the new radius after collapse is 8.3 x 10^6 m. Participants confirm that the angular velocity is calculated as 2π/38 days, affirming the relationship between angular momentum and the new period post-collapse.

PREREQUISITES
  • Understanding of conservation of angular momentum
  • Familiarity with the moment of inertia formula (I = 2/5mr^2)
  • Basic knowledge of angular velocity calculations
  • Concept of celestial mechanics and stellar evolution
NEXT STEPS
  • Study the derivation of angular momentum conservation in astrophysical contexts
  • Learn about the implications of stellar collapse on angular velocity
  • Explore the moment of inertia for different celestial bodies
  • Investigate the effects of mass distribution on rotational dynamics
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Astronomy students, astrophysicists, and anyone interested in the dynamics of stellar evolution and angular momentum conservation.

cheez
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Suppose a sun has a radius of 8.1 x10^8 m and a period of 38 days. If is collapses to a dwarf of radius 8.3 x 10^6 m, what is the new period (in days)? I= 2/5mr^2
I totally don't know how to do the problem. :frown:
Is it related to conservation of angular momentum?
Does the angular velocity equal to 2pi/38 days?
thx!
 
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Yes - to both questions! :)
 
Tide said:
Yes - to both questions! :)
thx, I get the answer now :)
 

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