Recent content by a.k

Homework Statement The wind exerts a force of 420 N toward the south on the sails of Gerry’s sailboat, while the water exerts a force on the sailboat of 160 N west.The boat and Gerry have a combined mass of 320 kg, what are the magnitude and direction of the sailboat’s acceleration...

Vy=ayt Vx=axt Vy=-68.6 m/s Vx=38.5 m/s V=sqrt(38.5^2+-68.6^2) sqrt(6188.21) V=78.67 m/s

Ok I am working on part c and ax is actually 5.5 m/s^2. I am confusing myself.

So part a, x=1/2axt^2 1/2(5.5)(7)^2 269.5/2 x=134.75 m Im not sure if using "x" is correct. It is suppose to show horizontal accel, so ax?

Ok, I figured out some more info. on this problem. For part b, t=sqrt(2y/ay) 2*-240.1 sqrt(49) t=7 secs

Homework Statement A 2.0kg physics book is dropped from the roof of a skyscraper 240.1 m high. While the book is falling to the ground, a horizontal wind exerts a constant force of 11 N on it. Ignore air resistance. a. How far from the building is the book when it hits the ground? b. How...

Homework Statement Santa arrives at the local mall by helicopter and, as the helicopter steadily descends at 1.0 m/s, he releases a bag of candy to the children waiting below. After 3 seconds: a. what is the speed of the bag of candy? b. how far is it below Santa’s helicopter? c. What are...

64 m/s^2+(-19.6m/s)(-30m) 64+588 vf2=652 sqrt(652) 25.53 Due to descending, it is -25.53 m/s t=vf-vi/-9.8 m/s^2 =-17.3/-9.8=1.765 t=1.77 seconds

Homework Statement A man using a hang glider who is descending at a speed of 8 m/s drops his cell phone from an altitude of 30 m. a. How long does it take the cell phone to reach the ground? b. What is the velocity of the cell phone just before it hits the ground?Homework Equations...

Time Question -- how long did the train block the crossing? Homework Statement A commuter train 500 m long travels on a straight track at a speed of 78.6 km/h it slows down as it approaches a crossing. The last car passes the crossing at a speed of 15.8 km/h. With a constant acceleration, how...

I don't know either tiny tim. I am happy I was able to figure it out though.

Unfortunately so. I am curious if this is correct: 5/7*4mph and 5/7*3mph 20/7 and 15/7 2.86 and 2.14 miles 2.86-2.14= 0.14 miles west of the fountain I think I got this by a fluke by using d=tv then subtracted the mileage.

I still don't understand.

Thank you for the response.

Homework Statement Two joggers are approaching a water fountain from opposite directions. Jogger A begins 3.0 miles west of the water fountain, with a constant velocity of 4.0 mph due east. Jogger B begins 2.0 miles east of the water fountain, with a constant velocity of 3.0 mph due west. How...