Time Question - how long did the train block the crossing?

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Homework Help Overview

The discussion revolves around a physics problem involving a commuter train that blocks a crossing. The original poster presents a scenario where a 500 m long train travels at varying speeds, and the goal is to determine how long it blocks the crossing while decelerating.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the time the train blocks the crossing using average velocity and distance. Some participants suggest alternative methods for calculating average velocity and express concerns about the use of averages in general.

Discussion Status

Participants have provided feedback on the original poster's calculations, affirming the correctness of the approach while offering minor suggestions for efficiency. There is an exploration of different methods to analyze the problem, with some participants questioning the assumptions made regarding the intersection's length.

Contextual Notes

There is a mention of the train's deceleration and the varying speeds of the train's front and rear, which may affect the interpretation of the blockage time. Additionally, the length of the intersection is noted as a factor that could influence the overall time calculation.

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Time Question -- how long did the train block the crossing?

Homework Statement


A commuter train 500 m long travels on a straight track at a speed of 78.6 km/h it slows down as it approaches a crossing. The last car passes the crossing at a speed of 15.8 km/h. With a constant acceleration, how long did the train block the crossing?


Homework Equations


avg v=(v0+vf)/2
t=change x/avg v


The Attempt at a Solution


First I converted 78.6km/h*1000m/km*1h/3600 secs=78600/3600=21.83 m/s
Secondly I converted 15.8km/h*1000m/km*3600h/3600secs=15800/3600=4.39 m/s

Using avg v=21.83+4.39/2=13.11 m/s

t=500m/13.11m/s
t=38.14s

I am pretty sure I did this correctly, but it took me a long time figuring it out (like what to do first and what equations to use). Any advice?
 
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It looks like you did it correctly. When you're first learning a new subject, you've got to figure that it's going to take you longer than when you gain more experience. Nice job.

Chet
 
Looks good to me too. My only advise would be to take the average velocity BEFORE you convert it into m/s. Then you just convert the average km/h to m/s. The way you did it is just fine. This would just save a LITTLE time, since you'd only have to do that conversion once.
 
I personally shy away from 'averages' since I've been burned more than once by them. In this case it's of course OK.
But you could approach the problem more formally:
Keeping our eye on the front of the train only,

v(t) = v(0) + ∫0t a(t')dt'
= v(0) +at since a is constant.
So v(T) = v(0) + aT where T = total time of intersection blockage. ... (1)
Then, s(t) = distance traveled by head of locomotive until the intersection is cleared
= ∫0t v(t')dt' + s(0) but s(0) = 0,
= ∫0t(v(0) + at')dt'
and s(T) = v(0)T + aT2/2 = 0.5 ... (2)

Now you can solve (1) and (2) for T and a.

BTW this ignores the length of the intersection. The intersection is actually blocked from the moment the locomotive first intersects with the near end and stays blocked until the last wagon passes the far end, so our answer for T is too short for any finite length intersection. :eek:
 

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