Recent content by aaronmorg

It seemed right because I calculated 26.14 in-lbf as the energy delivered by the Rubberband. I converted 26.14 in-lbf to 2.1783 ft-lbf by dividing by 12. Horizontal Velocity: VH=\sqrt{(\frac{2(2.1783)ft-lbf}{27.999g})[\frac{453.6g}{1lbm}][32.2\frac{lbm-ft}{lbf-s2}]} Comes out to...

I talked to my engineering teacher and he said I was going about it the wrong way. I need, at least, 50% Lift. So I reworked my equation and came out with FL=\frac{(.76764)(.076\frac{lbm}{ft^2})(56.55 in^2)(\frac{47.67\frac{ft}{s}^2}{2})[\frac{ft^2}{144 in^2}]}{[32.2\frac{lbm-ft}{lbf-s^2}]} I...

Thanks :D I'll go try converting to metric units and I'll let you know how everything turns out! I appreciate the help.

I am stumped on how to convert my units for the equation for Force of Lift. FL=CLPA\frac{v^{2}}{2} My equation comes out to: FL=(.76764)(.076\frac{lbm}{ft})(\frac{(65.899\frac{ft}{s})^{2}}{2}) Still figuring out this equation hypertext stuff. Please help if you can. I am supposed to...

I found the equation for Horizontal Velocity. Here it is for anyone else who might be stuck in the same place. VH=\sqrt{\frac{2E}{m}} E is energy m is mass In my case Energy was elasticity since my glider was flung from a rubber band. So I had to find ft-lbf, then use different conversion...

I am working on my semester project and have come across a hitch. I am trying to find the Lift Force of my wing using the following equation FL=CL P A (v2/2) Where: FL is Lift Force CL is Coefficient of Lift (I think) P is the density of the fluid (Air) A is the Area V is Velocity...