Recent content by abc617

Well I have \mathcal{L}^{-1}(\frac{1}{s + a}) = e^{-at} So I assume the answer should be: x(t) = \mathcal{L}^{-1}(\frac{1}{s+\frac{2}{3}}) = e^{\frac{-2}{3}t}?

Oh, I forgot the 2, so it should've been x(t) = 2e^{-t}?

Alright so factoring out and canceling: X = \frac{2s + 4}{s^2 + 3s + 2} = \frac{2(s + 2)}{(s + 2)(s + 1)} = 2\frac{1}{s+1} So then I would take the inverse Laplace transform of 2\frac{1}{s+1} To get: x(t) = e^{-t}

Alright so I tried redoing it and this is what I redid: -Resimplified the equation X(s) \frac{3(3s+2)}{9s^{2}+12s+4} => \frac{3(3s+2)}{(3s+2)(3s+2)} => \frac{3}{3s+2} The problem here is that I don't know if there is an inverse transformation for the denominator because there is a...

So my professor is really bad and I've had to try to learn to learn this stuff myself. But I have no idea where to start and where to go. Problem: X(s) = \frac{3(3s+2)}{9s^{2}+12s+4}Attempt All I've been able to figure out so far is: -> X(s) = \frac{3}{(3s+2)^{2}} * \frac{1}{(3s+2)}} But...

Thanks, apparently I put in s^1 and mistook it for s' Alright so I rewrote X = \frac{2s + 4}{s^2 + 3s + 2} = \frac{2(s + 2)}{(s + 2)(s + 1)} as X = \frac{2}{(s+2)(s+1)} * \frac{s+2}{(s+2)(s+1)} -I was then able to cancel s+2 in the 2nd term. -Then by using a Laplace transform table...

In this engineering course I'm taking I'm learning how to solve Laplace transforms. Now my ODE class only barely touched on this so I'm not sure if I'm doing this correct so I'd like some help pointing out where I went wrong, if I went wrong anywhere. x''(t) + 3 x'(t) + 2x(t) = 0, x(0) = 2...

http://img243.imageshack.us/img243/156/55139700.png Knowns Well I know that \sum \frac{1}{1-x} = 1+x^{2}+x^{3}... I know the integral is [PLAIN]http://www4a.wolframalpha.com/Calculate/MSP/MSP32919a6dgiib73geda500000hd72bah4i062h1b?MSPStoreType=image/gif&s=36&w=241&h=38 I've...

Well after simplifying that inequality, I get the intervals to be (x=0, x=8), and like I said before, it still isn't correct. Did I make a mistake somewhere else?

Find the interval of convergence for the given power series. http://img52.imageshack.us/img52/3632/c1786dba870d63ff1a827d9.png The series is convergent from x= ___ to x = ____ Attempt [PLAIN][PLAIN]http://img412.imageshack.us/img412/7411/image00.jpg Attempted...