Recent content by abdo99

I know that ,but i did not konw the maximum H The rule is H=(u^2sin^2)/2g

Attempt solution Y=(vsinø)t-0.5gt^2 4=(vsinø)t-4,9t^2 But there is 3 variables! Another eq is X=(vcosø)t 6=(vcosø)t But i did not found any away to solution