abdo99
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Attempt solution
Y=(vsinø)t-0.5gt^2
4=(vsinø)t-4,9t^2
But there is 3 variables!
Another eq is
X=(vcosø)t
6=(vcosø)t
But i did not found any away to solution
Question in dynamics projectile motion
- Thread starter abdo99
- Start date
3 replies · 1K views · last reply
Attempt solution
Y=(vsinø)t-0.5gt^2
4=(vsinø)t-4,9t^2
But there is 3 variables!
Another eq is
X=(vcosø)t
6=(vcosø)t
But i did not found any away to solution
Discussion
dauto
- 1,948
- 201
You posted a sideways picture
rtsswmdktbmhw
- 38
- 2
Hint: 1. The ball travels on a parabolic path.
2. If you know the max height of the ball, you can calculate the vertical and horizontal components of initial velocity.
Or, at least, that's how I managed to do it but there may be a simpler method/formula..
2. If you know the max height of the ball, you can calculate the vertical and horizontal components of initial velocity.
Or, at least, that's how I managed to do it but there may be a simpler method/formula..
Last edited:
abdo99
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I know that ,but i did not konw the maximum H
The rule is H=(u^2sin^2)/2g
The rule is H=(u^2sin^2)/2g