- #1
abdo99
- 2
- 0
Attempt solution
Y=(vsinø)t-0.5gt^2
4=(vsinø)t-4,9t^2
But there is 3 variables!
Another eq is
X=(vcosø)t
6=(vcosø)t
But i did not found any away to solution
Question in dynamics projectile motion
- Thread starter abdo99
- Start date
Click For Summary
Homework Help Overview
The discussion revolves around a dynamics problem involving projectile motion, specifically analyzing the motion of a ball projected at an angle. Participants are exploring the relationships between vertical and horizontal components of motion given certain parameters.
Discussion Character
- Exploratory, Assumption checking, Conceptual clarification
Approaches and Questions Raised
- The original poster attempts to set up equations based on vertical and horizontal motion but expresses difficulty due to having three variables. Some participants suggest using the maximum height to find the initial velocity components, while others question the availability of that information.
Discussion Status
Participants are actively discussing the problem, with hints provided regarding the nature of projectile motion and potential approaches to find the initial velocity components. There is recognition of the need for additional information, particularly the maximum height, to proceed effectively.
Contextual Notes
There is mention of a specific rule for calculating maximum height, but the original poster indicates a lack of knowledge regarding that value, which may affect their ability to solve the problem.
Attempt solution
Y=(vsinø)t-0.5gt^2
4=(vsinø)t-4,9t^2
But there is 3 variables!
Another eq is
X=(vcosø)t
6=(vcosø)t
But i did not found any away to solution
- #2
dauto
- 1,948
- 201
You posted a sideways picture
- #3
rtsswmdktbmhw
- 38
- 2
Hint: 1. The ball travels on a parabolic path.
2. If you know the max height of the ball, you can calculate the vertical and horizontal components of initial velocity.
Or, at least, that's how I managed to do it but there may be a simpler method/formula..
2. If you know the max height of the ball, you can calculate the vertical and horizontal components of initial velocity.
Or, at least, that's how I managed to do it but there may be a simpler method/formula..
Last edited:
- #4
abdo99
- 2
- 0
I know that ,but i did not konw the maximum H
The rule is H=(u^2sin^2)/2g
The rule is H=(u^2sin^2)/2g
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