May 26, 2014 #1 abdo99 Messages 2 Reaction score 0 Attempt solution Y=(vsinø)t-0.5gt^2 4=(vsinø)t-4,9t^2 But there is 3 variables! Another eq is X=(vcosø)t 6=(vcosø)t But i did not found any away to solution
Attempt solution Y=(vsinø)t-0.5gt^2 4=(vsinø)t-4,9t^2 But there is 3 variables! Another eq is X=(vcosø)t 6=(vcosø)t But i did not found any away to solution
May 26, 2014 #3 rtsswmdktbmhw Messages 38 Reaction score 2 Hint: 1. The ball travels on a parabolic path. 2. If you know the max height of the ball, you can calculate the vertical and horizontal components of initial velocity. Or, at least, that's how I managed to do it but there may be a simpler method/formula.. Last edited: May 26, 2014
Hint: 1. The ball travels on a parabolic path. 2. If you know the max height of the ball, you can calculate the vertical and horizontal components of initial velocity. Or, at least, that's how I managed to do it but there may be a simpler method/formula..
May 27, 2014 #4 abdo99 Messages 2 Reaction score 0 I know that ,but i did not konw the maximum H The rule is H=(u^2sin^2)/2g