when the (pendulum + cart)system moves along the inclined plane, they do not feel the effect of any gravity in that direction as if they were in free fall in the sliding direction.
so, what remains is the g component perpendiculur to the slide direction, which is your effective g in this case.
one of the terms x1, or x2 will get negative
we are measuring them from their eqilibrium positions
this means that the equation holds for both the cases
and yes ,were x1 and x2 magnitudes of displacement only ,what you have put forth
would hol beyond doubt.
what do you think is the compression of the middle spring,
1/2(kx^2),right
where x is the cange in length of the middle spring ,that is (x^2 = (x1-x2)^2)
No
O(t=0)----------------------->vt(point A)(source)
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Point B(you)
I want you to find the component of source’s(A) velocity
Along the line joining point A & point B at an instant t
And plug that velocity into your equation for vs.
some mechanism which can measure the speeds of incoming cars, send signals, pulls up breaks and activates some magnetic repulsion, saves the day for two cars onto each other but there are other objects which can be a problem.
but the idea is cool and should be used in the time to come...
think of a large number and you can think of an even larger number, this doesn't ends anywhere. infinity is that number which is larger than every number you can think of and hence acts as a limit to such numbers which are still open at the top. you can see it like all numbers bigger than...