Recent content by Abrar Quadery

while diagonalizing an operator A with a matrix S (formed from eigenvectors of A), does S need to be unitary (i.e., whether I have to form it with the NORMALIZED eigenvectors)? Even if S is not unitary, A gets diagonalized.

Suppose, i want to diagonalize operator A by matrix S (A'= S^\\dagger A S). Do i need to form S from "NORMALIZED" eigenvectors? I checked and found that even S formed from not-normalized eigenvectors works.