Diagonalize operator A by matrix S

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SUMMARY

The discussion centers on the diagonalization of operator A using matrix S, expressed as A' = S† A S. It is confirmed that S does not need to be formed from normalized eigenvectors; S can be constructed from non-normalized eigenvectors as well. However, while a diagonal matrix is produced, the diagonal elements will not correspond to the eigenvalues of A if S is not normalized. This highlights the importance of using normalized eigenvectors for accurate eigenvalue representation.

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Abrar Quadery
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Suppose, i want to diagonalize operator A by matrix S (A'= S^\\dagger A S). Do i need to form S from "NORMALIZED" eigenvectors? I checked and found that even S formed from not-normalized eigenvectors works.
 
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If S isn't normalized, you will get a diagonal matrix. However, the diagonal elements of the matrix will not be the eigenvalues of A.
 

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