I wish there was an emoticon for an embarrassed slap to one's own forehead. I can't believe I made such an amateurish move. I guess I somehow convinced myself that (a + b)x was equal to ax + bx and then multiplied both terms by x. I was just trying to simplify my integral before trying to...
∫0m5m (F cos θ) dx
= F∫0m5m (cos θ) dx
= F∫0m5m [x(x2 + 25)-1/2] dx
= F∫0m5m [1 + (x/5)] dx
= F{∫0m5m dx + 1/5∫0m5m x dx}
= F{[x + x2/10]5m0m}
= F{[(5 m) + (5 m)2/10] - [0]}
= F(7.5 m), where F= 756 N
= 5670 J
This just seems to be too high a value to me. Since the x...
Homework Statement
A 76-kg crate starts from rest at A and is moving at 8 m/s. Using integration, find the work done between A and B of the variable x component of force F= 756 N. (See attached jpeg for the geometry of the problem)
EDIT: We are doing a variation of the problem shown in the...