Recent content by adjoint+
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Graduate What happens to an electron's energy after Bremsstrahlung radiation?
Yes, sorry electron, I corrected the question.- adjoint+
- Post #4
- Forum: High Energy, Nuclear, Particle Physics
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Graduate What happens to an electron's energy after Bremsstrahlung radiation?
So, if an electron with 60 KeV interacts with the nucleus of a target material such that all of its energy is converted into an x-ray photon of energy 60 KeV, what happens to that electron now since it has 'no energy'?- adjoint+
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate What happens to an electron's energy after Bremsstrahlung radiation?
What happens to an electron after it has undergone Bremsstrahlung and all its energy has been converted into an x-ray photon?- adjoint+
- Thread
- Bremsstrahlung Radiation
- Replies: 4
- Forum: High Energy, Nuclear, Particle Physics
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Engineering Physics or engineering? Going into university this fall and still unsure
Do physics. Career in medical physics.- adjoint+
- Post #2
- Forum: STEM Career Guidance
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Undergrad X-ray spectra- bremsstrahlung and characteristic x-rays
Thanks! I guess this makes sense.- adjoint+
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Undergrad X-ray spectra- bremsstrahlung and characteristic x-rays
Hi all, In an x-ray spectrum, the curve part represents the bremsstrahlung part, and the spikes are the characteristics x-rays. Characteristic x-rays represent a discrete energy. However, in many textbooks, I noticed that the characteristic x-rays are often represented as a peak, which implies...- adjoint+
- Thread
- Bremsstrahlung Characteristic Spectra X-ray X-rays
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics
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Graduate Dirac Delta Function vs probability distribution
Hello, Can someone please explain to me how to do the following: 2/a * integrate sin^2(n*pi*x/a)*delta(x-a/2)dx from 0 to a. The delta function is defined for the limit -infinity to infinity, right? How do I do this one? The limits of integration in this case is what I'm finding...- adjoint+
- Post #16
- Forum: Quantum Physics