I X-ray spectra- bremsstrahlung and characteristic x-rays

adjoint+
Messages
7
Reaction score
0
Hi all,

In an x-ray spectrum, the curve part represents the bremsstrahlung part, and the spikes are the characteristics x-rays. Characteristic x-rays represent a discrete energy. However, in many textbooks, I noticed that the characteristic x-rays are often represented as a peak, which implies a range of energies.

Can anyone help me understand why this is so? Am I missing something?
Thanks!
 
Physics news on Phys.org
adjoint+ said:
However, in many textbooks, I noticed that the characteristic x-rays are often represented as a peak, which implies a range of energies.
In any experimental measurement a wave length or frequency is a number but the intensity plot will have a spread due to uncertainty in measurement and it comes out like a peak with a small spread...this width say at half maximum is a measure of uncertainty ...as well as the state of emitter of that line ...if the source is in thermal motion the width increases .
Even in visible spectrum say Sodium doublet lines D1 and D2 you will find a width of emission lines.

Moreover if somebody tries to measure exactly the frequency i.e. the energy of the characteristic emission the Heisenberg Uncertainty relation will give an infinite width of the time span of measurement ...as uncertainty in energy and time multiplied together should be of the order of Planck's constant.
 
  • Like
Likes geoelectronics and adjoint+
Thanks! I guess this makes sense.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top