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All right, can u explain this http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam2/fa06 Question 15 I assumed it would be positve, so if i do right hand rule, i have force is up so Electric field would have to point down CorrecT? so why is it negative

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam1/sp06 Why am i stuck on 14 and 15 The equation that i would use would be F = Kq1Q2 / R^2 correct? and all it is is just plug and chug but i am not getting the answer

Homework Statement http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam1/fa06 Homework Equations W =F*D The Attempt at a Solution I have it solved, now i thought - would be if i put work into the thing to move it but looking at it since both of...

Ignore everything that is above me http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/sp00 QUestion 25 and 26

All right, i got all the stuff up there, i just need help on this one http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/fa04 Why is A wrong? So if the focal Length is 5 for the convex then they were converge there

You are forgeting that M = -di/do Formula = (1/do + 1/di) = (1/f) So 4do = - di 1/do - 1/4do = 1 1/4do - 4/4do = 1 3/4do = 1 do = .75

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/sp04 Question 6 What would be the answer? It is C but i want to know how to solve it. thanks

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/sp04 QUestion 2 is this something i would have to just know or can i get it form I/d + 1/ O = 1 /F

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/fa05 Question 6 So i found the focal length and it is 12.5 cm which happens to be the answer. now i just want to make sure that it will be true for other problems if the magnification is half the...

more info please :) Edit: Actually this is what i did Sin Theta = ( 2.5)(600*10^-9) / ( .3*10^-3) = .005 Sin Theta = (3.5)(600 * 10^-9) / (.3*10^-3) = .007 Angle is .28648 Angle is .40107 Y = Tan theta * L Did it for both of them, subtracted and i got 1 mm, is the way i...

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/sp05 Question 8 So the first one since it is horizontal would be I1 = I0/ 2 so this is only true if it is horizontal or verticle

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/sp06 Question 19. How do u find what order fringe the 2nd and 3rd are in that pic?

http://online.physics.uiuc.edu/cgi/courses/shell/phys102/fall06/prep2a.pl?practice/exam3/sp06 Questions 4-6 , i don't need it to be solved, i just need to know whether my equations are right cause i have somone else's answers and i don't know how he got them. he Has I1 = I0 / 2 which doesn't...

.00315 m ...

got the answer, thanks