Recent content by amanda.ka
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Solve for 2D Elastic Collision: Find θ & φ Angles
So I solve the first equation for cosφ and the second equation for sinφ? 1.341cosφ = 2-cosθ and -1.341sinφ = sinθ then square each term: 1.3412cos2φ = 22-cos2θ and -1.3412sin2φ = sin2θ then I added them but I'm still a bit lost/don't know the next step :/ 1.3412cos2φ + (-1.341)2sin2φ =...- amanda.ka
- Post #3
- Forum: Introductory Physics Homework Help
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Solve for 2D Elastic Collision: Find θ & φ Angles
Homework Statement A 2D elastic collision: Two pucks (masses m1 = 0.5 kg and m2 = 0.3 kg) collide on a frictionless air-hockey table. Puck 1 has an initial velocity of 4 m/s in the positive x direction and a final velocity of 2 m/s in an unknown direction, θ. Puck 2 is initially at rest. Find...- amanda.ka
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- 2d Collision Elastic Elastic collision
- Replies: 4
- Forum: Introductory Physics Homework Help
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Why Does ADAMTS4 Knockout Show Least Staining If It Cleaves Aggrecan in Mice?
thank you!- amanda.ka
- Post #3
- Forum: Biology and Medical
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Why Does ADAMTS4 Knockout Show Least Staining If It Cleaves Aggrecan in Mice?
-Aggrecan is an abundant component of cartilage within the growth plate as well as the articular cartilage of joints -ADAMTS4 and ADAMTS5 are aggrecanases that cleave aggrecan -Analysis of the growth plates of mice were performed by immunostaining the growth plates with an antibody against...- amanda.ka
- Thread
- Study
- Replies: 2
- Forum: Biology and Medical
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Calculating Pump Power and Fountain Height from Water Ejection Speed
Thank you for your help!- amanda.ka
- Post #20
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
Kf + Uf = Ki + Ui 0 + (500)(9.81)h = 1/2(500)(20^2) + 0 Now I get the same answer as I originally got but with a positive sign- amanda.ka
- Post #18
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
Would the initial U be negative 12 since it is below the well? If I take the top of the well as a reference point (zero) then the water would initially start -12 m below that- amanda.ka
- Post #16
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
Kf + Uf = Ki + Ui = 1/2mv^2 + mgh = 1/2mv^2 + mgh = 100,000 + (500)(9.81)h = 0 + (500)(9.81)(12) = 100, 000 + 4905h = 58,860 41140 = - 4905 h h = -8.387 m My answer is still negative, is something wrong with the initial/final values ?- amanda.ka
- Post #14
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
K(final) + U (final) = K(initial) + U (initial) ? Sorry I don't think I am understanding the concept :(- amanda.ka
- Post #12
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
Is it the change in work?- amanda.ka
- Post #10
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
It represents the change in kinetic energy- amanda.ka
- Post #8
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
It represents the total energy Emech = K + U, should it be equal to zero (conservation of energy)?- amanda.ka
- Post #6
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
For my equation i tried to do -1/2v^2 = mgh then solve for h but I think that is incorrect because I did get a negative :/- amanda.ka
- Post #4
- Forum: Introductory Physics Homework Help
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Calculating Pump Power and Fountain Height from Water Ejection Speed
Homework Statement A pump draws 500 kg of water/min from a 12 m deep well. The water is ejected with a speed of 20 m/s. a) What is the power output of the pump? b) How high is the fountain (ignoring air resistance) Homework Equations The Attempt at a Solution For part a I found the potential...- amanda.ka
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- Output Power Power output Pump
- Replies: 20
- Forum: Introductory Physics Homework Help