Recent content by Amr Morsi

Thanks Anonym for this advise. You are right... One has to revise many many things. You are absolutely right: "The adequate QFT should contain naturally electroweak and QCD (at least)". Thanks for the alert. I may continue in your way. See you. Amr Morsi...

My_Wan,:smile: I agree with you on this. And this can be easily deduced by a fundamental situation and then to be safely and securely generalized. The rule is concerned with locally-fixed-particles body, not any system. And this is done in many of the mechanics-specialized books. But, I...

Buddies, This small file may help more about the concept of QFTs. It also inlcudes the link to the source. Haelfix, lamb shift is not a correction in QFT or QM, it is only a consequence. No doubt between these days, or before that DIRAC'S IS THE RELATIVISTIC SHRODINGER EQUATION. Forgive...

:smile: Hi Tomaz / All, Thanks to hear for the following, maybe it will end up the long debate. Let's not get into deep mathematical discussions. The main debated problem here is the physical rule. By the way, no scientist until these days said that Newtonian mechanics are wrong in...

Just to add Vandslire, Some fluctuations (I mean gravitomagnetic furnituring) spreads by a velocity less than that of light. But, in general, when speaking about curvature transition, we are referring to gravitational waves, which are through speed of light. No matter, they discovered it...

:cool: Vandslire, Of course, there are some features of the GR Equations that make some difficulties in our imagination of the situation. This is the main problem that lead some scientists to interpret it as another concept. Away from boundaries upon transformations and fluctuations as...

Karlis, Since the equation includes total derivative with respect to t, then x, y and z are functions of t as already included in the argument of F; X(t) .... However, you still can solve it, but in terms of dx/dt, dy/dt, dz/dt ... etc. But, here, only function in dx/dt, dy/dt and dz/dt...

Sheyr, Electrodynamics deals with charges, even in motion, through Maxwell's Equations, and on an individual basis. Quantum Mechanics and Quantum Field Mechanics, however, deal with the situation from another point of view. It speakes about the probability of finding a charge (or a...

T. Finder, That's right, these equations are absolutely right. But the problem is that many some scietists now are talking about the origin of field quantization to be due to the probability of photon itself. What do you think? No doubt, the wave function in QFTs are that of the charges...

Indention spoken about by some scientists is in two aspects, one in relativity "or, space science, generally speaking" and the other is in quantum mechanics. The former is related to high frequency fuctuations. The latter, however, is relatted to what is posted as vacuum polarizability. Jim...

Nexus555, As already mentioned before, you are just trying to get the whole thing into mind. I know that it is very hard that you get my answer. But, whenever you get it, this is my answer. Moreover, as I learned from these long trials in the field of research in electromagnetism...

Then, for approximately static gravitational field, the gravitational field of a vanishing star will be canceled after L/C "Roughly speaking", ended by ubrupt gravitomagnetic change and then null effect. Engineer\ Amr Morsi.

Gravity and Gravitomagnetic Fluctuatuations are transmitted through space by light velocity as believed by most scientists now. There are two faces to deal with the theory. One of which is the gravitomagnetic concept... It is very similar to magnetic field in electromagnetism, also speed is the...

Daniel, Absolutely speaking in a Maxwellian Basis: F> = q E>+ q v> x B> + Fself> , where Fself> is a drag force on the moving charge that depends upon the acceleration vector. If we are talking about description and understanding, then I can say: This can be solved in the frame of the...

LittileHilbrt; Let y=c+id, where y^2=z. Then; c^2-d^2+2i c*d=a+ib. As a result; a=c^2-d^2 (eq1) and b=2c*d (eq2). Therefore, from eq1 and eq2; c^2 = a + (b/c)^2/4 (eq3); Solving eq3 in c^2, we get c^2={a+sqr(a^2+b^2)}^.5 /2 Therefore, c=(+/-) sqr({a+mod(z)}/2)...