Recent content by anbhadane

Anyway I am now clear with my doubt. 2T - H is another form of L so basically it's the same as L. I was interested in only T + V. Thank you for your valuable responses.

Thank you. Now I got it.

I know in action we use lagrangian which is T - V, but i am saying instead of T-V, can we use T+V? anyway it's function too.

sorry, I was saying action with energy as function.

so, basically we find first path and it automatically satisfies the minimum energy requirement?

I know that by extremizing lagrangian we get equations of motions. But what if we extremize the energy? I am just little bit of confused, any help is appreciated.

Oh, Thank you, got it.

In Jackson,(3rd edition) Chapter 1 , page no, 44 He uses the word "semipositive definite" what is it? is it "non-negative" definite?

Oh, similar way of expansion, calculations on 547, are done. In Jackson's (p.547) equation such as (11.94) , (11.96), (11.98) are expanded by Taylor expansion.

Oh,sorry , got it.

Now I got it. I was thinking in very different way. First one was easy, and second one is essentially taylor expansion. But here we are just taking approximation, thank you all of you.

yes doubts are questions. Oh, I come to know about the first part but still for second question how is it possible to have metric tensor equal to exponential of metric tensor?

In Jackson, (3rd edition p. 545), there are equations they are given as, $$A = e^L $$ $$det A = det(e^L) = e^{Tr L}$$ $$g\widetilde{A}g = A^{-1} $$ $$ A = e^L , g\widetilde{A}g = e^{{g\widetilde{L}g}} , A^{-1} = e^{-L}$$ $$ g\widetilde{L}g = -L $$ I have several doubts. 1) $$det(e^L) =...

Myself doing physics undergraduate in college. I have many doubts some concepts and want to clear them. Hope this community is as good as stackexhange.