Recent content by anthraxiom

I got it thanks

My bad...

its just saying that A moves to B with 5m/s and B moves towards A at 5m/s

I tried to solve using trigonometry. Let angle between line CA ad BA be theta and angle between BA and AC be alpha. 30sin theta= 40 sin alpha 30 cos theta + 40 cos alpha + 2vt=50 I have no idea how to proceed after this.

after conversion I get around 14.683 ton-force

The acceleration would have to be expressed as a function of time and various answers can be gotten for different functions. However, I am going to assume that you mean the acceleration is constant and that the truck started from rest. using second equation of motion, 1/2 at2 - ut=s u=0, t=1,s=1...

thanks :D

I simply don't know where I'm going wrong in this. lets for example say y=2x. dy/dx=y/x=2 now if we look at only the differential equation we see that dy/y=dx/x, solving we get x=y I have no idea how this is happening, please , if possible guide my foolish thoughts to where I have gone wrong.

Oh thank you so much I've been banging my head about this for 3 hours.

I solved the for time but for distance am quite confused on why the approach im trying doesn't work. First, let acceleration=w w=-a√v w=dv/dt=-a√v rearranging, √v dv=-a dt integrating both sides, v0V∫√v dv=0T∫-a dt where V is some arbitrary velocity at time T. we get, (2√V)-(2√v0)=-aT------eqn...

yes my friend did make it up on the fly

i really didn't want to find the answer per se i just wanted to see if an expression could be found which is the cause for the bizarre numbers. I really thought a solution could be attained pehaps.

I gave the parameters so that i couldn't just brute force through the question by calculating each one but thanks for the graph :D

I actually read that question first before i thought about this one

oh right i forgot about that, thanks