Force to move a 24 tonne truck one foot in one second

[Rev. Cheeseman]

The acceleration in one second over one foot distance is 0.6096 m/s2. So, F=m⋅a=24,000×0.6096=14,630.4N

Therefore, the force required to move a 24-tonne truck one foot in one second (from rest):

• Force = 14,630.4 N
• ≈ 3,289.5 lbf
• ≈ 1.492 tonnes-force

Is that correct?

 

[anthraxiom]

The acceleration would have to be expressed as a function of time and various answers can be gotten for different functions. However, I am going to assume that you mean the acceleration is constant and that the truck started from rest. using second equation of motion, 1/2 at² - ut=s
u=0, t=1,s=1
substituting, a/2=1,
a=2ft/s²
using F=ma,
F=24 tonne ⊗2ft/s²=48 tonne ft s^-2

 

[Rev. Cheeseman]

The acceleration would have to be expressed as a function of time and various answers can be gotten for different functions. However, I am going to assume that you mean the acceleration is constant and that the truck started from rest. using second equation of motion, 1/2 at² - ut=s
u=0, t=1,s=1
substituting, a/2=1,
a=2ft/s²
using F=ma,
F=24 tonne ⊗2ft/s²=48 tonne ft s^-2

If we want to find just the force and assuming we want to find the force to push the 24 tonne truck in one second over a distance of one foot, is it around 1.5 tonne?

 

[anthraxiom]

If we want to find just the force and assuming we want to find the force to push the 24 tonne truck in one second over a distance of one foot, is it around 1.5 tonne?

after conversion I get around 14.683 ton-force

 

[Baluncore]

Mass = 24 Mg, in 1 second ; 1 foot = 0.3048 m .
s = u⋅t + ½⋅a⋅t² ; t = 1 ; u = 0 .
a = 2 * s = 0.6096 = 0.6096 m⋅s^-2
F = 24 Mg * 0.6096 = 14.6304 MN = 14630.4 kN
14630.4 / 9.8 = 1524. kg force = 1.524 tonne force.

 

[Rev. Cheeseman]

after conversion I get around 14.683 ton-force

Mass = 24 Mg, in 1 second ; 1 foot = 0.3048 m .
a = 2 * s = 0.6096 = 0.6096 m⋅s^-2
F = 24 Mg * 0.6096 = 14.6304 MN = 14630.4 kN
14630.4 / 9.8 = 1524. kg force = 1.524 tonne force.

Thank you so much, guys.

 

[Rev. Cheeseman]

Mass = 24 Mg, in 1 second ; 1 foot = 0.3048 m .
a = 2 * s = 0.6096 = 0.6096 m⋅s^-2
F = 24 Mg * 0.6096 = 14.6304 MN = 14630.4 kN
14630.4 / 9.8 = 1524. kg force = 1.524 tonne force.

Sorry, where did 9.8 figure came from?

 

[Baluncore]

F = m⋅a = m⋅g
g = 9.8 m⋅s^-2

 

[Baluncore]

Note that the "ton" is a customary unit;
The metric, ISO, or SI "tonne" = 1000 kg.
The "short ton", (common in the USA) = 2000 pounds = 907.184 kg.
The "long ton" (once common in the UK) = 2240 pounds = 1016.047 kg.
It is wise to avoid the unspecified "ton".

 

[Lnewqban]

If we want to find just the force and assuming we want to find the force to push the 24 tonne truck in one second over a distance of one foot, is it around 1.5 tonne?

It seems that you are using tonne for force and mass simultaneously.

Copied from:
https://en.m.wikipedia.org/wiki/Tonne

“The tonne (symbol: t) is a unit of mass equal to 1,000 kilograms.
.....
In contrast to the tonne as a mass unit, the tonne-force is not accepted for use with SI.”

 

[Baluncore]

Tonne force is used, even if the SI does not like it.
https://en.wikipedia.org/wiki/Ton-force