Recent content by ArmiAldi

let me know is this correct or no? dx)/(x lnx^4) (dx)/(x 4lnx) (dx)/(4x lnx) u = lnx du/dx = 1/x (du)(x) = dx lnx = u dx = (du)(x) (du)(x)/(4x u) du/4u (1/4)ln(u) (1/4)ln(lnx)

i have 2 simmilar questions 1) Find the equation of the line tangent to the curve at the point xy + y = 2 ; (1, 1) and i did this xy + y = 2 y + xy' + y' = 0 xy' + y' = - y y'(x + 1) = -y y' = -y/(x + 1) y' = -1/2 y- y_1 = m(x - x_1) and i hope so this is OK but how can i...

Need answers for 2 questions please: 1.) Find the equation of the line tangent to the curve at the point. xy + y = 2 ; (1,1) 2.) Evaluate dy/dt for the function at the point xy^2 = 4 dx/dt = -5 x = 4, y = 1 Thank You