- #1

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1.) Find the equation of the line tangent to the curve at the point.

xy + y = 2 ; (1,1)

2.) Evaluate dy/dt for the function at the point

xy^2 = 4 dx/dt = -5 x = 4, y = 1

Thank You

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- Thread starter ArmiAldi
- Start date

- #1

- 3

- 0

1.) Find the equation of the line tangent to the curve at the point.

xy + y = 2 ; (1,1)

2.) Evaluate dy/dt for the function at the point

xy^2 = 4 dx/dt = -5 x = 4, y = 1

Thank You

- #2

- 211

- 1

May I direct your attention to : https://www.physicsforums.com/showthread.php?t=44101

- #3

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