You mean the integral of this don't you?ArmiAldi said:let me know is this correct or no?
dx)/(x lnx^4)
Well, (1/4) ln(ln(x))+ C. And you didn't really need to write "(du)(x)/(4x u)". From du/dx= 1/x, du= dx/x and you can go ahead and substitute du for the dx/x you already have in the integral.(dx)/(x 4lnx)
(dx)/(4x lnx)
u = lnx
du/dx = 1/x
(du)(x) = dx
lnx = u dx = (du)(x)
(du)(x)/(4x u)
du/4u
(1/4)ln(u)
(1/4)ln(lnx)
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