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Ok ty (can u checked this one)

  1. May 4, 2008 #1
    let me know is this correct or no?
    dx)/(x lnx^4)
    (dx)/(x 4lnx)
    (dx)/(4x lnx)
    u = lnx
    du/dx = 1/x
    (du)(x) = dx

    lnx = u dx = (du)(x)

    (du)(x)/(4x u)

  2. jcsd
  3. May 4, 2008 #2


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    I am moving this question to the homework forums. Please post all homework/coursework questions there in future!
  4. May 5, 2008 #3


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    You mean the integral of this don't you?

    Well, (1/4) ln(ln(x))+ C. And you didn't really need to write "(du)(x)/(4x u)". From du/dx= 1/x, du= dx/x and you can go ahead and substitute du for the dx/x you already have in the integral.
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