Recent content by as2528

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    Calculations involving different Dielectrics and Capacitors

    Thank you! This cleared it up for me.
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    Calculations involving different Dielectrics and Capacitors

    And it was the microjoules.
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    Calculations involving different Dielectrics and Capacitors

    That was u=.5c*v^2. So I calculated with charge which causes the error?
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    Calculations involving different Dielectrics and Capacitors

    Table 25-1 was a table showing a few dielectric constants along with the materials they corresponded to. I was supposed to get 4.7 from the question, which was the part I failed on. On the table it said Pyrex was corresponding to that kappa.
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    Calculations involving different Dielectrics and Capacitors

    TL;DR Summary: Need dielectric constant for given capacitor Given a 7.4 pF air-filled capacitor, you are asked to convert it to a capacitor that can store up to 7.4 mJ with a maximum potential difference of 652 V. Which dielectric in Table 25-1 should you use to fill the gap in the capacitor...
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    Final velocity involving a can of soup and an inclined plane

    Oh, I see! Thanks for clearing that up! While I knew about static friction, I didn't know about rotational energy leaching gravitational energy. That perfectly explains why my acceleration was higher using the sliding formula. Thanks!
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    Final velocity involving a can of soup and an inclined plane

    Got it! Thanks I didn't realize the formula I was using was assuming slipping. Guess I learned a new thing about it!
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    Final velocity involving a can of soup and an inclined plane

    Yes the 1.50 seconds was also part of the problem. I accidentally omitted the sentence. I have updated the problem.
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    Final velocity involving a can of soup and an inclined plane

    a = 9.8*sin(25*pi/180)=>a=4.1417 m/s^2 vf^2=vi^2+2*a*s=>vf=sqrt(0^2+2*4.1417*3)=>vf=4.9850 m/s Meanwhile the correct answer is: (vf+vi)/2=>(vf+0)/2=2=>vf=4 m/s Why is my answer wrong? It seems that the acceleration is what is wrong, but I don't understand why.
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    Moment of inertia problem involving a cylinder rolling down an incline

    Oh! I did not realize that. Thanks!
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    Moment of inertia problem involving a cylinder rolling down an incline

    No I used it from the question. It said that the height was 10.8 cm. I converted that to meters and reasoned that since gravity is conservative I could use .108 as the height of the soup can.
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    Moment of inertia problem involving a cylinder rolling down an incline

    The .108 was supposed to be the height of the incline.
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    Moment of inertia problem involving a cylinder rolling down an incline

    a=2/3*g*sin(25*(pi/180))=>a=2.8507 m/s^2 vf=vi+at=>vf=0+2.8507*1.50=>vf=4.2760 m/s So the translational motion of the cylinder is 4.2760 m/s. 4.2760=R*w w=134.04 rad/s PE=mgh=>PE=215*9.8*.108=>PE=227.56 J PE = KE at the end of the roll because of energy conservation. 227.56 =...
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    I What is the Purpose of Torque?

    Thank you! I think I understand it better now.
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    I What is the Purpose of Torque?

    From what I understand about torque, it is basically the power of the force to cause a change in an object's rotational motion. It is easier to cause this change when the force is applied further from the point of rotation than closer, which is why it is difficult to open a door by pressing a...
    • as2528
    • Thread
    • Torque Torque and rotation
    • Replies: 7
    • Forum: Mechanics