Recent content by ash312

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    What Must Superman's Initial Velocity Be to Save the Falling Student?

    Homework Statement A student is determined to test the law of gravity for himself. He steps off a skyscraper 320m high, stopwatch in hand, and starts his free fall. Five seconds later, superman arrives at the scene and dives off the roof to save the student. What must superman's initial...
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    How long does a ball stay in the air when hit at 18 m/s?

    Homework Statement A baseball player hits the ball straight up in the air with a velocity of 18.0m/s. As soon as the ball is hit, the runner on third base dashes toward the home plate. The distance between third base and home plate is 27.4m. Where will the runner be with reference to home...
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    Will a car stop before reaching a broken bridge 150 m away?

    LOL! yes She gets to survive! we saved her! Anyway Thanks a lot! i think i learned somthint here!
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    Will a car stop before reaching a broken bridge 150 m away?

    OMG! i made a careless mistake... i forogot to put in the 1 before 190.44...! :( ok then she stopped within 41.4 m. Which means she didnt fall over the bridge rihgt?
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    Will a car stop before reaching a broken bridge 150 m away?

    Ok, do i square root my answer? If i do then i got 13.6
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    Will a car stop before reaching a broken bridge 150 m away?

    185.84? sorry it took so long... i didnt no the reply was in the second page.. i was waiting for it in the first page! :=)
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    Will a car stop before reaching a broken bridge 150 m away?

    V^2 = 190.44 + 2 * (-2.3) D i need to calculate D
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    Will a car stop before reaching a broken bridge 150 m away?

    ok.. i understand, 130.68 can go into it because that is the distance she has to stop not the distance it takes her to stop.. so what do i put in instead of 130.68? 19.32?
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    Will a car stop before reaching a broken bridge 150 m away?

    OK i did it but i don't think its right: = 13.8^2 + 2 (-2.3) (130.68) = 190.44 + (-0.3) (130.68) = 190.44 + (-39.204) = 151.236 Do i square root the answer? if this is right...