What Must Superman's Initial Velocity Be to Save the Falling Student?

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SUMMARY

The discussion centers on calculating Superman's initial velocity required to catch a falling student from a height of 320 meters. The student, in free fall for five seconds, reaches a speed of approximately 79 m/s just before impact. The relevant physics equation used is v² = v₁² + 2aΔd, where 'a' represents acceleration due to gravity. The calculations confirm that the student's speed is accurate, contingent on the gravitational constant used.

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ash312
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Homework Statement


A student is determined to test the law of gravity for himself. He steps off a skyscraper 320m high, stopwatch in hand, and starts his free fall. Five seconds later, superman arrives at the scene and dives off the roof to save the student. What must superman's initial velocity be in order to catch the student just before the student reaches the ground? Assume superman obeys the laws of physics like any other free falling objects

Homework Equations



v2^2 = v1^2+2aΔd

The Attempt at a Solution


I used the formula above to calculate that the student will be traveling at 79m/s just before he hits the ground. But i think i have the wrong approach
 
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ash312 said:

Homework Statement


A student is determined to test the law of gravity for himself. He steps off a skyscraper 320m high, stopwatch in hand, and starts his free fall. Five seconds later, superman arrives at the scene and dives off the roof to save the student. What must superman's initial velocity be in order to catch the student just before the student reaches the ground? Assume superman obeys the laws of physics like any other free falling objects


Homework Equations



v2^2 = v1^2+2aΔd



The Attempt at a Solution


I used the formula above to calculate that the student will be traveling at 79m/s just before he hits the ground. But i think i have the wrong approach

That is the correct speed for the student - or very close; depends what value for g you used.
 

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