Recent content by awesome_irl

  1. A

    Find Tension in Cables for 13 kg & 4 kg Signs

    @ phizkid the "13 g" doesn't denote the mass, I think you mistook the g as a gram rather than the acceleration of gravity. Yoy're correct in mentioning that the system is motionless so that's why the net force is 0 for both the x and y components.
  2. A

    Find Tension in Cables for 13 kg & 4 kg Signs

    Just wondering...was my first attempt correct (my physics teacher posted the answer and her t1 was 131.18 N) I know I sound paranoid but still... -_-
  3. A

    Find Tension in Cables for 13 kg & 4 kg Signs

    Thanks! Oh! And merry christmas
  4. A

    Find Tension in Cables for 13 kg & 4 kg Signs

    Homework Statement The big sign below (see attached image) is 13 kg and the small sign is 4 kg. Find the tension in all 4 cables. Homework Equations Fnet= Fa +FbThe Attempt at a Solution ƩFx= T2cos38 - T1cos51=0 T2=T1cos51/cos38 ƩFy=T1sin51 + (T1cos51/cos38)sin38 - 127.4 -39.2 = 0 T1=131.303
  5. A

    Is the problem wrong (deals with resolving vectors into their components)?

    Thanks!
  6. A

    Is the problem wrong (deals with resolving vectors into their components)?

    I just realized that T1 stood for vector V I thought that T1 somehow was identifying Vector y I feel stupid...REALLY stupid...
  7. A

    Is the problem wrong (deals with resolving vectors into their components)?

    Homework Statement 4.9b cites the y components to be sin degree and 4.9a is somehow cos degree for the x components (see picture) Homework Equations Here's a different textbook that supports my claim (see picture) The Attempt at a Solution Shouldn't the y components for problem 4.9b be cos...
Back
Top