Yes, you're right. I have one more question: what prompted you to assume that the period remains the same? Why couldn't the EMF remain constant and the period change by some factor?
You're right! However, the question never asked for the peak value, it just said "new voltage". Is it implicit that I provide the peak value? As for the frequency, it would remain the same as we assumed the period to remain constant, thus 50 Hz.
Oh I see what you're referring to when you say "acts of kindness" :) ! I felt compelled to work on the problem so I took the closest book I could find and tried my best.
The formula I acquired in my solutions suggests I merely have to divide 129.45 by the period (0.02 s because frequency is 50 Hz). Sorry about the unit, I certainly included it in my test. Also, it's not a requirement that I round to sig figs in my test but I'll be sure to do so from now in this...
That makes a lot of sense. Thank you for helping me see it, the period remains unchanged because it no where states in the question that it was changed. So the new emf, when rounded up, is 6473 emf.
This was a question on a test I previously had. Faraday's law: Є= (NxBxA)/T. Where N is the number of turns, B is the magnetic field strength and T is the period. This is the formula I was given on the test. As you can see above in my attempt of the solution, I got stuck when I had an equation...
Sorry.
The initial peak EMF and frequency in the generator (AC) are 1220 V and 50 Hz respectively. The magnetic field is halved, the area of the coil is tripled and the number of turns increases from 50 to 250. What is the new EMF and frequency?
How would you explain this as though you were writing a log book for this experiment, recording observations for this data qualitatively as your teachers have not yet taught you the probability mass function of the Poisson point process? Again, I am certain that what you are saying has merit and...