Recent content by banshee43

Thanks for the info this gives me a good jumping off point to start to actually understand the different methods. Do you have any suggestions as to a method for pressure differentials or is it included in the methods? It is not necessarily that I want to design the blades but for my...

Hi there, I think this is in the right section if not please inform me and move my thread. I want to design and build a UAV in a copter format whether it be quad, hexa, octa, ect. I want to make a modeling software so that I can design the most efficient blade/motor for my specific needs. I am a...

yes i am using a limit and i forgot about the 2, i guess it converges to 1/2 then? i had forgotten that the ratio test needed a limit because i wasnt in class when we learned it.

Using the ratio test because there are constants raised to powers i get.. (2^(n+1)/(4^(n+1)+1))*((4^(n)+1)/2^n) then using some algerbra (4^(n)+1)/(4*4^(n)+1) and some more algerbra... gives me 1/4 which is <1 therefore the series converges?

I thought that it looked funky when I did it. Thank you though

So can that 1 be represented by a 1^n? Because no matter what n is Given n>=0 that 1^n = 1.?

sorry i didnt put enough parentheses my series is 2^n/((4^n)+1)

Homework Statement Can you if given a sigma notation for an infinite series Ʃ 2^n/(4^n+1) rewrite as, Ʃ 2^n/(4^n+1^n) then doing the root test can you lim n→∞ n^√abs((2/(4+1))^n) which equals 2/5, and 2/5<1, therefore can i conclude that the series above converges? Sorry...

Homework Statement a region that resists a body of water follows the curve y=.3x^2 from 0<=y<=240 using water density of 1000 kg/m^3 and g of 9.8 m/sec^2 Homework Equations 0 to 240∫g(rho)(240-y)2(sqrt(y/.3) The Attempt at a Solution 9.8(1000)(2)(240^(3/2)(292.199-.730297(240)) i...

thankyou very much! i just didnt exhaust my formulas..

Homework Statement ∫sin(t)cos(2t)dt Homework Equations cos(2t)=1-2sin^2(t) The Attempt at a Solution ∫sint(t)(1-2sin^2(t))dt but where do i go from here? i can't use substitution. or parts?

Yes, I believe have. Using prime notation: ln^2(6x)' u=ln^2(6x) u'=2ln(6x)ln(6x)' u'=2ln(6x)/(6x)*(6x)' u'=2ln(6x)/(6x)*6 since ((6x^1)' = *Const*x^n=*Const*nx^n-1 in my case 6x^1 = 1*6x^1-1 the 6's cancel and you are left with u'=2ln(6x)/x :)

yes! thank you so much... those simple mistakes will be the death of me!

is it because the -2 is distributed and not +2?

Hi all this is my first post hopefully i do it right. Homework Statement integrate ln^2(6x)dx The Attempt at a Solution *integral* ln^2(6x)dx u=ln^2(6x) dv=dx du=(2ln(6x))/x dx v=x xln^2(6x)-*integral*x(2ln(6x))/x dx xln^2(6x)-2*integral*ln(6x) dx u=ln(6x) dv=dx du=1/x...