Physics applications of integrals

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SUMMARY

The discussion focuses on the application of integrals in physics, specifically in calculating the force exerted by water on a curve defined by the equation y = 0.3x², within the bounds of 0 ≤ y ≤ 240. The relevant physical constants include a water density of 1000 kg/m³ and gravitational acceleration of 9.8 m/s². The integral used for the calculation is from 0 to 240 of the expression g(ρ)(240 - y)²(sqrt(y/0.3). A participant attempted to solve the problem, arriving at a numerical result of 8,520,997,056, but noted that the problem statement lacked clarity.

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  • Understanding of integral calculus, particularly in physics applications
  • Familiarity with the concepts of density and gravitational force
  • Knowledge of the properties of parabolic curves
  • Ability to manipulate and evaluate definite integrals
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banshee43
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Homework Statement


a region that resists a body of water follows the curve y=.3x^2 from 0<=y<=240
using water density of 1000 kg/m^3 and g of 9.8 m/sec^2


Homework Equations


0 to 240∫g(rho)(240-y)2(sqrt(y/.3)


The Attempt at a Solution


9.8(1000)(2)(240^(3/2)(292.199-.730297(240))
i think it is 8520997056
 
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Your problem statement is incomplete and makes no sense.

What do you mean by "a region that resists a body of water..."?
 

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