Recent content by Batman4t

I solved it: Using the spring constant that I found: F(x) = kx I found the new Work (W) done for the new distance using: W = (1/2)k(x2)^2 - (1/2)k(x1)^2 Then with the new amount of work done used the equation Wtotal = (delta)K. So... W(new) = (1/2)m(v2)^2 - (1/2)m(v1)^2...

Sorry, When the spring again returns to its unstretched length, what is the speed of the attached object?

[SOLVED] velocity of a spring Homework Statement https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/IAState/phys221/spring/homework/05/block_spring_nofriction/4.gif A spring is stretched a distance of Dx = 40.0 cm beyond its relaxed length. Attached to the end of the spring...

Homework Statement A disk with a radial line painted on it is mounted on an axle perpendicular to it and running through its center. It is initially at rest, with the line at q0 = -90.0°. The disk then undergoes constant angular acceleration. After accelerating for 3.15 s, the reference line...