Recent content by Bazzinga

Great I'll take a look at those! Thanks!

I've got a tricky computational statistics problem and I was wondering if anyone could help me solve it. Okay, so in your left pocket is a penny and in your right pocket is a dime. On a fair toss, the probability of showing a head is p for the penny and d for the dime. You randomly chooses a...

Hey guys, I'm trying to find a conditional distribution based on the following information: ##Y|u Poisson(u \lambda)##, where ##u~Gamma( \phi)## and ##Y~NegBinomial(\frac{\lambda \phi}{1+ \lambda \phi}, \phi^{-1})## I want to find the conditional distribution ##u|Y## Here's what I've got so...

Hey guys, I was wondering if you could help me out with a question I've got, I really don't know where to go or really where to start! Here's the question: Let S be a subspace of a finite dimensional vector space V. Show that there exists a Linear Mapping L: V → V such that the kernel of L is...

Oh I think I just got it... \sum^{n=1}_{infinity}(1/2)(1/2)^{n-1}=\frac{1/2}{1-(1/2)}=1 durr

Ok, but there's this example in my textbook: \sum^{n=1}_{infinity}(1/2)^{n}=\frac{1/2}{1-(1/2)}=1 "The series is a geometric series with a=1/2 and r=1/2" I'm confused as to how a=1/2

Oh! Everything would cancel out except a - ar^n S - r*S = a - ar^n ... S = a(1 - r^n)/(1-r) which explains why -1<r<1 since the limit n->inf r^n would diverge above 1

So far in class to find the sum we've just been comparing everything to the geometric series or using a bound on the error, so no

But judging by what everyones been saying, I'm assuming if n=1, then the sum is a/(1-r) and if it starts at 0 you have to multiply everything by r, making the actual sum ar/(1-r) EDIT: n=1 to infinity of course

I was hoping someone could help me understand how to find the actual sum of the geometric series, whether it starts at n=0, n=1 or n=N or whatever!

Keep your panties on ladies, I was making a pun

No idea how to figure it out, want to help me through it instead of being a dick, Dick?

Ok I just looked at another question and it does have n=1 to infinity, but it still defines the sum like: (1/4)/(1-(1/4))

how about n=1->infinity? The textbook doesn't say, it just says that's the sum =\ I'm assuming its n=1->inf though

So the textbook is wrong? What is the actual sum of the geometric series then?