Bazzinga
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I'm confused about the sum of the geometric series:
\sum ar^{n-1} = \frac{a}{1-r} when |r|<1
but if you have a series like:
\sum (1/4)^{n-1}
the sum is:
\frac{1/4}{1-(1/4)}
should't it be \frac{1}{1-(1/4)} because there is no a value?
\sum ar^{n-1} = \frac{a}{1-r} when |r|<1
but if you have a series like:
\sum (1/4)^{n-1}
the sum is:
\frac{1/4}{1-(1/4)}
should't it be \frac{1}{1-(1/4)} because there is no a value?