Recent content by beborche

@rude man, thanks for your explanation. Also thanks for pointing me in the direction of Lenz's law. I should've revisited that one before even posting the question here.

Ok guys. Thanks for your replies. This was driving me nuts. From your answer, phyzguy, I take it there's no correct way of determining the direction of dS? Whatever floats your boat?

Homework Statement There's a magnetic field B in +\hat{z}. A rectangular loop is lying in the xy-plane. Three sides are static, the 4th one is moving with velocity v along the direction of +\hat{y}, making the rectangular larger and larger. The length of this moving side of the rectangle is L...

@ehild Alright. I get it now. Tanv will produce the same result for all angles v + n*pi, where n=1, 2, 3... Thank you!

Homework Statement Write arctan8 + arctan11 as an expression containing max one term with arctan.Homework Equations tan(u+v) = \frac{tanu+tanv}{1-tanutanv} arctan(tanx) = xThe Attempt at a Solution u = arctan8, v = arctan11 tan(u+v) = \frac{tanu+tanv}{1-tanutanv} = \frac{8+11}{1-8*11} =...

Alright. Yes i meant 1/(4sqrt(3)).

@BruceW Thanks man. I knew I could just hit arcsin(1/7) in on my calculator to find the angle and then from there find the adjacent side, but we're not allowed to use the calculator. But then I realized you meant Pythagoras theorem, which I ofcourse didnt think about... Thanks again! I think...

Homework Statement Calculate tan(arcsin(1/7))Homework Equations arcsinv = x => sinx = v sinx = (opposite/hypotenuse) (in a right-angled triangle) tanx = (opposite/adjacent) The Attempt at a Solution Well I realize that arcsin(1/7) is an angle. Let's call it v. I also know that arcsin(1/7)...

Thank you, I solved it! Not by finding acceleration in the case of friction first, but thanks to you reminding me of that what I calculated was the average velocity. These two lines messed it up: v = s/t = 2.67 m/s a = (v-u)/t = 0.71 m/s² Where it says (v-u), it should say 2*v. Since v = average...

Ah you're right. I see the mistake. F = ma = mgsin\theta - ukgcos\theta Rearrange and you'll get this uk = \frac{a + gsin\theta}{gcos\theta} = \frac{0.71 + 9.8sin(35)}{9.8cos(35)} = 0.787 should be F = ma = mgsin\theta - ukmgcos\theta Rearrange and you'll get this uk = \frac{a -...

Homework Statement A pig is sliding down a ramp that has an angle of 35 degrees from the horizontal plane. If the friction coefficient was 0 the ride would only take half the time. What is the kinetic friction coefficient between pig and ramp?Homework Equations Fnet = ma v² = u² + 2as a =...

Alright, then I understand. Savvy :) And thanks for explaining.

I understand everything except where m²/s² comes from. Unless they are the units for v², i.e. velocity squared? (In that case, why no units for gravity or mass?) thanks // Beborche

Credits to you! :P 0,175m is the correct answer. I don't understand a few things just yet but I'll dive into it and see if I get grasp it. Thanks a lot! and brb

I didn't miss it when I did ma calculations. Edited now! But can you see where I go wrong?