Recent content by Benny

There isn't much difference, it's just that I've been using cartesian tensor methods and an identity involving the epsilon and delta tensors to do problems with with cross products. I won't have much free time in the next few weeks so if you're interested in different notations my suggestion...

I can't believe this thread was revived after well over a year. It brings back memories though. This was one of the problems I was struggling on while working through my problem booklet. Since then I've learned to use the summtation convention and I can get the answer out in a few lines...

I can't remember much linear algebra but I would try considering the following. Suppose the dimension of a vector space is 6. Is it possible to extract 7 linearly independent vectors from that vector space?

Don't worry, I'm not one of the regulars there. Your username just seemed familiar that's all.

I hope your situation gets better. I'm inclined to think that you'd be best to stay in Australia. At your age it wouldn't be easy to adapt to such a big change. By the way, are you the same Vanush from a popular NSW based student message board?

Try setting u = 1/x or something like that.

Thanks for the explanation.

Hi, I'm just trying to get a feel for a subject that I plan to take but I'm unsure about the meaning of a certain term which frequently arises. The term 'flow' comes up a lot and I'm wondering what it could mean (or refers to) in the context of a pipe flow problem. I know my question is vague...

You seem to be trying to base your career objective on the scores that you obtain. IMO that's not always the best way to go about choosing the discipline you want to go into. I'm pretty sure that once you get past undergrad it's more about your understanding rather than your ability to do...

At first glance I agree with your first answer for res(f,-2) but not for res(f,1). g\left( z \right) = \frac{{e^z }}{{\left( {z + 2} \right)}} \Rightarrow g'\left( z \right) = \frac{{e^z }}{{\left( {z + 2} \right)}} - \frac{{e^z }}{{\left( {z + 2} \right)^2 }}

Thanks for the help. The first part of the question involved deriving the Green's function for the 3D laplacian but the question statement itself isn't clear cut on whether an answer in terms of G is acceptable or if the expression for the G must be used. So presumably, an integral expression...

Homework Statement Consider \nabla ^2 u = Q\left( {x,y,z} \right) in the half space region z > 0 where u(x,y,o) = 0. The relevant Green's function is G(x,y,z|x',y',z'). Find the solution to the PDE in terms of G. If Q\left( {x,y,z} \right) = x^2 e^{ - z} \delta \left( {x - 2}...

The answer said it was a pole.:redface: I guess in future I should use my judgement when looking at the answers. Thanks for the help.

I found the singularities by setting z^4 - 1 = 0. The first term in the series for the sin(pi*z), centred at 1, is zero but the second one (which is something multiplied by (z-1)) isn't. So the singularity should be removable but then it isn't a simple pole. It makes no difference to the...

Hi I'm just working on an integral where I need to classify the singularities of the integrand \frac{{\sin \left( {\pi z} \right)}}{{z^4 - 1}}. There are singularities at z = \pm 1, \pm i but the ones I'm interested in are at z = \pm 1. \frac{{\sin \left( {\pi z} \right)}}{{z^4 -...