berkeman's latest activity
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The moon and Venus, today's evening -
berkeman reacted to jedishrfu's post in the thread Forbes Daily Newsletter: 10% decline in student CompSci enrollment with
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From the Forbes daily newsletter June 17, 2026: -
berkeman replied to the thread High School Anyone come across this new YouTube channel?.After deleting a post with an insult, the thread is reopened provisionally.
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berkeman replied to the thread High School Anyone come across this new YouTube channel?.Thread is closed temporarily for Moderation.
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berkeman replied to the thread Electrical Building an AI integrated speedometer for the cycle.I'll attach a picture of my MTB speedometer magnet and pickup below. The magnet has a screw that attaches it to one of the spokes on...
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berkeman reacted to jedishrfu's post in the thread PHP My website presents the visitor with the choice of opting out of using cookies.... with Informative.
Cookie law is a funny beast. Each country or region may have a different take on it. The law is based on where the user is from and not...
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berkeman replied to the thread My introduction to Physics Form Community.Welcome to PF! :smile:
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berkeman reacted to m_varshika's post in the thread My introduction to Physics Form Community with
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Hello intelligent people! I am a Chemical Engineering undergrad student with little knowledge and interest in everything. I am... -
berkeman reacted to Jaime Rudas's post in the thread High School Anyone come across this new YouTube channel? with Like.
If the universe is infinite, can it become even vaster?
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berkeman replied to the thread High School Anyone come across this new YouTube channel?.Maybe if we ignore normal English grammar modulo artistic license. o0)
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berkeman reacted to FactChecker's post in the thread Undergrad Question about increasing laser power with Like.
You are asking if we do impossible things, can impossible things happen. Yes.
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berkeman reacted to kuruman's post in the thread Undergrad Descartes’ Geometry of Square Roots with Like.
Trigonometric proof ##\theta +\varphi=90^{\circ}## Therefore ##\tan\theta=\cot\varphi\implies \tan\theta \tan\varphi=1.##...
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berkeman reacted to renormalize's post in the thread Undergrad Descartes’ Geometry of Square Roots with Like.
##r^{2}=h^{2}+\left(r-a\right)^{2}\Rightarrow h^{2}=2ar-a^{2}=a\left(2r-a\right)=ab\Rightarrow h=\sqrt{ab}\quad\blacksquare##
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berkeman reacted to bob012345's post in the thread Undergrad Descartes’ Geometry of Square Roots with Like.
In the figure below of a semi-circle, show that ##h=\sqrt{ab}##. In the special case where ##a=1## unit length, then ##h=\sqrt{b}##. A...
