Recent content by bigwuying

Thanks for answering me! The following is wrong reasoning,but i still can caculate the answers second card a club- p1=1/4 First card not a club and not an ace 36/52, second card not a club 38/51 p2=(36X38)/(51X52) First card is a club and not an ace 12/52 , second card not a club...

Yes, you are right. i only know how to use chain rule, but i don't know what it is actually. When i start to learn Partial Derivative, i find it difficult to understand why dw/dt appear 3 term, and why do dx and dx not be eliminate. To understand this problem ,i have read my text and start...

There is a theorem in partial derivative If x= x(t) , y= y(t), z= z(t) are differentiable at t_{0}, and if w= f(x,y,z) is differentiable at the point (x,y,z)=(x(t),y(t),z(t)),then w=f(x(t),y(t),z(t)) is differentiable at t and \frac{dw}{dt}=\frac{\partial w}{\partial x}\frac{dx}{dt} +...

\sumThe question is: You are involove in a game where two card are dealt consectively. Supposethat the dealer pays you $3of the second card dealt is a club, regardless of the first card and that you pay him $1 if the second card in not a club and the first card is not an ace. (othewise, no...