Recent content by bigzee20

Homework Statement A small first-aid kit is dropped by a rock climber who is descending steadily at 1.2 m/s. a) After 4.2 s, what is the velocity of the first-aid kit? Answer in units of m/s. Ok i know that the velocity after the 4.2 sec is -42.36 however the question asks how far is the...

ok here is what i did F1x = 36N cos110 = -12.31 F1y = 36N sin110 = 33.83 F2x = 22N cos130 = -14.14 F2y = 22N sin130 = 16.85 F3x = 28N cos20 = 26.31 F3y = 28N sin20 = 9.58 then i found the resultant for the x and y component

Consider 3 force vectors F1, F2, and F3. The vector F1 has magnitude F1 = 36N and direction θ = 110°; the vector F2 has magnitude F2 = 22N and direction θ = - 140°; and the vector F3 has magnitude F3 = 28N and direction θ = 20°. All the direction angles θ are measured from the positive x axis...

Ok i got the times 1. 9.725 sec 2. 71.7s 3. 11.05s

Anybody?

Homework Statement An automobile and train move together along parallel paths at 38.9 m/s. The automobile then undergoes a uniform acceleration of −4 m/s2 because of a red light and comes to rest. It remains at rest for 71.7 s, then accelerates back to a speed of 38.9 m/s at a rate of 3.52...

can someone help me solve this?

Iam confused man :confused:

For Car a what do i put in as time? i know car b is 1.4s? Car a = 1/2 (5.9)(?)^2+0(?) Car b = 1/2(4.1)1.4^2+0(1.4) = 4.018

Car a 1/2(5.9)(2.015)+0(2.015)= 5.94425 Car b 1/2(4.1(0.615)+0(0.615)=1.26075 Then 5.94425/1.26075 = 4.71sec

Hey tiny-tim thanks for the reply I used that formula on both cars then i divided their positions and that's how i got 4.68sec which is wrong. I don't know what iam doing wrong??

Homework Statement A race car driver buys a car that can accelerate at 5.9m/s^2. The racer decides to race against another driver in a souped up stock car. Both start from rest, but the stock car driver leaves 1.4s before the driver of the sports car. The stock car moves with an acceleration...

OMMMMG I love u I GOT IT! x=1/2a(t)^2 + Vi(t) Cops= 1/2(2.27)(12.15)+0(12.15) = 13.79025 Speeder= 1/2(0)12.15+27.6(12.15) = 335.34 335.34/13.79025 = 24.32s

Is there an specific formula for it?

How can i figure out the instantaneous position of an object using an acceleration time graph. Iam also given initial velocity and initial position? Thanks