Calculating Position from Acc. Time Graph

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SUMMARY

The discussion focuses on calculating the instantaneous position of an object using an acceleration-time (a-t) graph, given initial velocity and initial position. The area under the curve of the a-t graph represents the total change in velocity, while the area under the velocity-time (v-t) graph indicates the total change in displacement. The specific formulas for these calculations are essential for accurately determining position from the provided graphs.

PREREQUISITES
  • Understanding of kinematics principles
  • Familiarity with acceleration-time and velocity-time graphs
  • Knowledge of integral calculus for area calculations
  • Ability to apply initial conditions in motion equations
NEXT STEPS
  • Study the relationship between acceleration, velocity, and displacement in kinematics
  • Learn how to calculate the area under curves using integral calculus
  • Explore specific formulas for displacement from velocity-time graphs
  • Practice problems involving a-t and v-t graphs to reinforce concepts
USEFUL FOR

Students in physics, educators teaching kinematics, and anyone involved in motion analysis or engineering applications.

bigzee20
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How can i figure out the instantaneous position of an object using an acceleration time graph. Iam also given initial velocity and initial position? Thanks
 
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The area under the curve between two time points of the a-t graph is the total change in velocity between those two time points.

The area under the curve between two time points of the v-t graph is the total change in displacement between those two time points.
 
Is there an specific formula for it?
 

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