i think u r right somewhat. calculate the doppler shift of the wavelength as the entire range of visible region, i.e, 6600 angstorm minus 3900 angstorm. use the doppler shift of wavelength'' formula and get the actual speed of receeding. the actual wave length would be of UV (3900 angstorm). try...
yes u have to use the horizontal component of velocity in this case.
remember the velocity is zero at the topmost point only when the projectile is fired vertically, i.e, with zero horizontal component of velocity. if it is fired with some angle other than 90 deg with the horizontal it has a...
try to draw a free body diagram of both the masses seperately. assume the accln. to be the same for both the masses, because otherwise they would break contact (i.e. if B has more acln. than that of A, also think why it is not possible that B has less accln. than that of A) and hence there will...
i think u r wrong at taking the height that the object falls as 0.59m. actually the height should be 0.59 +x, where x is the compression of the spring. at that point there is no KE. so, the relevant eqn. should be (from conservation of energy),
mg(h+x) = 1/2 kx2.
this is a quadratic eqn. in x...
in yr eqn. a (acln.) should be replaced by (-g). t for ha eqn. is t and t for hb eqn. in t + tr. now subtract hb from ha. but this expression is true for t > tr. for 0<t<tr (that is the time interval when boris has not started his flight), D(t) = ha (as hb is zero for 0<t<tr). if this a textbook...
u r wrong in thinking that the man, as moving with const. velocity, exerts no force on balloon, where the actual case is the man starts from rest and acquires a velocity and in doing so acquires some accln. also, until he reaches a const. velocity and hence applies force to the balloon also...
first consider the switch is closed and current is flowing at steady rate(think about it, why it should flow at a steady rate? if u don't know it already), the value is given as 1mA. u can also calculate it from given data (how?), had it not given.
now consider the switch is suddenly open. the...
first, i think u have put it wrong, the time of 2nd projectile, it has been fired 1/2 sec later, so it will take less time to collide or travel the same distance with the first. so the time will be t1-1/2. 2nd-ly u can always find t1 in terms of cos alfa from the eqn. x1(t1) = x2(t2). replace t1...
for part b and c:
1.draw a neat diagram.
2.calculate the distance of the point at which the potential is to be calculated from each charged end of the dipole.
3. assume the charge and the separation of the charges of dipole.
4.relate this with the dipole moment given ( u can replace this...
here u used(or in the solution they used) the eqn. P*V/T = const. as pressure varies according to P = h*rho*g, 'the different pressure at differnt levels' can easily be understood. for the change of volume for different heights is only due to change in density. as air goes less dense a larger...
sorry, i was offline a bit long.
the key to this problem is to calculate the capacitance of the parallel plate when the combined slab is pulled a distance x toward +X axis. if u draw the figure u will see that the combined capacitance can be calculated from the combination of a series of...
for physical explanations for increase in current when a parallel resistance is added, think of the first wire getting fatter thus allowing more current to pass and since the voltage is same, desired result follows.
the induced emf may be given by e= dФ/dt, where Ф is the flux. now Ф can also can be given by Ф/area=B0. as the relation betwn r and t is given u can always find area as a function of time, hence also u can find dФ/dt and thus the expression for e ( B0 is const. e will be depending on rate...