Recent content by blader324

nevermind...i was able to figure it out...sorry about that :)

okay, so i have the problem tan(xy)=xy and i am told to implicitly differentiate in terms of x and y. when i do, i keep getting an indefinite answer. i need help because i know that's not right.

THANK YOU SO MUCH! ugh...you saved me learningphysics...MUCHAS GRACIAS!

sweet...so then for the momentum problem i got 21.99 as the final velocity...and then the work...i got the normal force as 15014.47 and then the work done by friction as -91888.56 Joules...is that right?

okay...so since the car isn't speeding up or slowing down, then the net forces in the y direction would be equal to zero?

okay...so the velocity doesn't change, and i just stick with the original component? as for the FBD, since the car isn't technically "accelerating" does that mean that i don't need to do a net force in the y direction=mass X acceleration in the y direction?

okay, so then would i use the 12m/s as the initial velocity for the ball for the momentum equation? because...the ball hits the car at the TOP of its motion, and doesn't that mean that the ball's velocity is zero?

for the third part (the work) i just drew a free body diagram of the car...and found that the normal force is 34614 N. i found the force of friction with that information (friction force=12461.04), and then i used the work equation. and got -211837 Joules

okay, so for the second part (momentum) that the initial velocity of the ball is zero because it's at the top of it's motion as it hits the car...so then, all i had was the mass and velocity of the car= (added masses)(added velocities)

Hey, i just wanted to check my answers with somebody on this question. It's an even number so i can't check with the back of the book, and my final is tomorrow. Here's the question: A soccer ball is kicked 56 degress above the ground at an inital velocity of 12m/s. the mass of the soccer ball...

alright...i'll stick to that explanation then. THANKS SO MUCH. take care...and my fingers are faster than my brain...but just to clarify...water is NOT adhesive...my mistake on that slip.

no...the tube is not sealed...so should i just stick with the capillary action, cohesiveness, and adhesiveness to describe the water being able to easily climb up a skinnier tube than a thicker tube?

okay...so the other thing i thought of last night was that the weight of the fluid inside the tube has to equal the atmospheric pressure outside the tube. if you have a smaller tube, the weight of the fluid inside of it is different than the weight of the fluid inside a larger tube... so in...

Homework Statement okay, so what I've been asked to do is explain why a liquid reaches a higher altitude in a skinnier test tube than in a wider test tube. i've brainstormed ideas...but i can't find the one that deals with pressure and tension and stuff like that...stuff that deals with...

exactly...so...without friction the person would fall down, but the fact that friction is present is preventing the person from slipping down, which means that friction is going upwards. THANK YOU SOOOOOOO MUCH! now all i have to do is the net forces in the x and y direction and then i'll...