Recent content by Blobikins

Homework Statement The board shown below is being held in equilibrium in the vertical plane by three smooth rods at A, B, and C Determine the magnitudes of forces at A, B, and C in terms of the weight of the body, W. Homework Equations Moment = f*r Here's a diagram The Attempt at a...

Homework Statement A 2000 kg plane is landing at an airfield with an initial speed of 50 m/s. The force of friction is 1/4 the weight of the plane. What is the acceleration of the plane? Homework Equations Fnet = ma Fnet = something - ff The Attempt at a Solution 2000a = thing I don't know...

Homework Statement A uniform steel beam has a mass of 1000kg. On it is resting half of an IDENTICAL beam, on one side. The length of the beam is L. The block and its' smaller counterpart are being held up by two poles, one on each side of the larger beam. What is the vertical support force for...

Thank you very much. I'm able to do any questions with ramps, and static friction in equilibrium, just combined masses were confusing me. Thank you.

I know this must be getting annoying, I'm sorry, but why? What difference does it make? (I'm not intending to be cocky, or snarky, I'm genuinely wondering.)

So, to calculate the acceleration of the mass hanging for force I use ma = fg(hanging) - fgsintheta, with the m for fnet being the total mass?

What exactly do you mean by component of weight? Like, fgcostheta?

For the two blocks connected merely on a string on a flat plane, I've figured out how to do acceleration (masses all added up), but can you just calculate tension by isolating a single one of the bricks, and using the f = ma to find Ft? Also, for the One mass hanging off an incline, I know you...

Homework Statement This is just a general question; but if there are two blocks attached with a string, how do you calculate acceleration and tension? Like, do you add the masses together and work with it, or do you do each separately? Also; if you have one block on an incline, and another...

Sorry, the cheese string is in fact parallel. The coefficient of friction between the cheese and the table is .60. I don't get how to find tension in the right string (the 30 degree one) without being given mass, because mass of the mouse determines the tension?

Homework Statement A .5 kg block of cheese sits on a level table. The coefficient of static friction is .60. Three strings are tied together in a knot at a point, K. One string is tied to the cheese, the other on a wall at a 30 degree angle, and in the middle of those two strings a mouse hangs...

So basically I'td be x - ?cos45 = vx d = 40 y = ?sin45 = viy d =10 a = -9.8 t = ? How do I put this together to make a proper equation

I don't know what you're getting at. Pick two solutions? I feel I'm missing a variable if I just have 45? What exactly do I do?

Apologies, I meant 2 solutions. Would it be possible for me to do a theoretical parabola where the midpoint is 80,20, so then a quarter of the time would be 40,10?

So, I was thinking so at 40m it's just reaching 10m, not the peak at that point. With the angle of 45 degrees, how do I do that?