Recent content by Blue Kangaroo
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Derivative of Cosine with unit vector
Ah I made a mistake. I meant to write ∂2E/∂r2- Blue Kangaroo
- Post #3
- Forum: Calculus and Beyond Homework Help
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Derivative of Cosine with unit vector
Homework Statement Take ∂2E/∂t2 E(r,t)=E0cos((k(u^·r−ct)+φ) in which u^ is a unit vector. Homework Equations d/dx(cosx)=-sinx The Attempt at a Solution I had calc 3 four years ago and can't for the life of me remember how to differentiate the unit vector. I came up with...- Blue Kangaroo
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- Cosine Derivative Unit Unit vector Vector
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Consistency of Faraday's Law and Electric Field Equation in Optics
Thank you, I should be able to take it from here.- Blue Kangaroo
- Post #3
- Forum: Introductory Physics Homework Help
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Consistency of Faraday's Law and Electric Field Equation in Optics
Homework Statement Suppose that an electric field is given by E(r,t)=E0cos(k·r−ωt+φ), where k⊥E0 and φ is a constant phase. Show that B(r,t)=((k×E)/ω)B(k⋅r-ωt+φ) is consistent with ∇×E=-∂B/∂t Homework Equations ∇×E=-∂B/∂t The Attempt at a Solution I know I have to take the curl of E, but I'm...- Blue Kangaroo
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- Faraday's law Law Optics
- Replies: 2
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
Yep, I've already done it. The rest went quickly once I knew what I was doing. Thanks.- Blue Kangaroo
- Post #19
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
Thanks for the help. Now that I take a step back and look at it, I was making it harder than it is.- Blue Kangaroo
- Post #17
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
OK, EQ=1(4πε0)(Q/d2)yhat- Blue Kangaroo
- Post #15
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
Q is the origin of EQ. Would EQ=Qd/α, or p=Qd? I feel like there's something I'm just struggling with in this section that I haven't in previous ones.- Blue Kangaroo
- Post #13
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
Would that expression be the dipole approximation? And both EQ and p would point in -y hat?- Blue Kangaroo
- Post #11
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
So then the E in the equation would be p=αEQ.- Blue Kangaroo
- Post #9
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
The field originates at the point charge Q and at the atom it is E=p/α I believe. Or am I just going in circles?- Blue Kangaroo
- Post #7
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
Well p=qd=αE, so E=qd/α?- Blue Kangaroo
- Post #5
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
According to my book, polarization is the dipole moment per unit volume, in units of C/m2. I believe polarizability is the ease with which something such as an atom is polarized. The polarizability is related to the dipole by p=αE..- Blue Kangaroo
- Post #3
- Forum: Introductory Physics Homework Help
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Polarizibility, Electric Field & Force
Homework Statement A neutral atom with known polarizability α is located at the origin. A point charge Q is situated on the y-axis a large distance d from the atom. (The atom therefore becomes polarized due to the electric field of the point charge.) (a) Find the electric field due to the atom...- Blue Kangaroo
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- E&m Elecricity Elecrostatics Elecrtomagnetism Electric Electric field Field Force
- Replies: 18
- Forum: Introductory Physics Homework Help
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LaTeX How Do I Insert an Excel Graph into LaTeX?
OK I solved the problem. I didn't realize I had to upload the file there. So I have that problem fixed. Now my problem is that it's putting the graph the wrong order. I wanted it to be before the conclusion, but for some reason it started the conclusion first and then place the graph the next...- Blue Kangaroo
- Post #8
- Forum: MATLAB, Maple, Mathematica, LaTeX